Question

A bag contains $6$ white balls numbered from $1$ to $6$ and $4$ red balls numbered from $7$ to $10$.
A ball is drawn at random. Find the probability of getting:
(i) An even numbered ball
(ii) A white ball

Answer 1

Number of white balls $=6$
Number of red balls $=4$
Total number of balls $=10$
Thus, $n\left(S\right)=10$
Let $A$ be event of getting number in even ball.
$A=\{2,4,6,8,10\}$
$n\left(A\right)=5$
$P\left(A\right)=\frac{n\left(A\right)}{n\left(S\right)}=\frac{5}{10}=\frac{1}{2}$
Let $B$ be event of getting white ball
$n\left(B\right)=6$
$P\left(B\right)=\frac{n\left(B\right)}{n\left(S\right)}=\frac{6}{10}=\frac{3}{5}$