A bag contains $7$ marbles: $3$ black, $2$ white and $2$ red. If you put your hand in the bag and draw out one marble, then find $P (n o t b l a c k)$ ?

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Solution

Finding the probability of not getting a black marble
The event here is not drawing a black marble from the bag containing marbles.
There are a total of $7$ marbles in the bag that can be drawn.
So, the total number of outcomes is $7$ .
There are $3$ black, $2$ white and $2$ red marbles in the bag that can be drawn.
So, the number of favorable outcomes is the number of white and red marbles,
$2 + 2 = 4$
The formula for probability is
$P r o b a b i l i t y = \frac{N u m b e r o f f a v o r a b l e o u t c o m e s}{T o t a l n u m b e r o f o u t c o m e s}$
$\Rightarrow P (n o t b l a c k) = \frac{4}{7}$
Hence, the probability of not getting a black marble is $\frac{4}{7}$ .

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