1
Question
A bag contains 7 white, 6 red and 2 black balls. One ball is taken out at random. Find the probability that the ball drawn is:
i) white
ii) neither red nor white
iii) either white or red or black
iv) not black
[4 MARKS]
i) white
ii) neither red nor white
iii) either white or red or black
iv) not black
[4 MARKS]
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Solution
Each subpart: 1 Mark each
Total number of balls = 7 + 6 + 2 = 15
i) Number of white balls = 7
P(white) =715
ii) Number of balls that are neither red or white =15−6−7=2
P(neither red nor white) =215
iii) Number of balls that are either white or red or black =7+6+2
P(either white or red or black) =1515=1 (sure event)
iv) Number of balls that are not black=15−2=13
P(not black) =1315
Total number of balls = 7 + 6 + 2 = 15
i) Number of white balls = 7
P(white) =715
ii) Number of balls that are neither red or white =15−6−7=2
P(neither red nor white) =215
iii) Number of balls that are either white or red or black =7+6+2
P(either white or red or black) =1515=1 (sure event)
iv) Number of balls that are not black=15−2=13
P(not black) =1315
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