Question

A bag contains 8 red, 2 black and 7 white balls. One ball is drawn at random. The probability that the ball drawn is not white is

• A. $\frac{5}{17}$
• B. $\frac{10}{17}$
• C. $\frac{2}{17}$
• D. $\frac{8}{17}$

Answer 1

The correct option is B

$\frac{10}{17}$

Total number of balls
= Number of red balls + Number of black balls + Number of white balls = 17
Number of white balls = 7
$\Rightarrow$ P (getting white ball) = $\frac{7}{17}$

$\because$ P (getting white ball) and P (not getting white ball) are complementary events

$\Rightarrow$ P (not getting white ball) + P(getting white ball)=1
$\Rightarrow$ P (not getting white ball)=1 - P(getting white balls) = $1-\frac{7}{17}=\frac{10}{17}$