A bag contains $8$ red balls, $11$ blue balls and $6$ green balls. Find the percentage of blue balls in the bag.

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Solution

Percentage of blue balls $= \frac{11}{8 + 11 + 6} \times 100 = \frac{11}{25} \times 100$
$= 44 %$
Hence, the answer is $44 % .$

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