A bag contains $9$ balls marked with digit $1, 2, . . . . . .9$ . If two balls are drawn from the bag, then numbers of ways getting the sum of the digits on balls as $10$

8

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2^{9}

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^{9} C_{2}

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^{9} P_{2}

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Solution

The correct option is A $8$
The possible ways of getting the sum as $10 :$
$1 + 9 2 + 8 3 + 7 6 + 4 4 + 6 3 + 7 2 + 8 1 + 9$
So they are $8$ ways

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Q. A bag contains 9 balls marked with the digits 1,2,3.....9. If two balls are drawn from the bag then find the number of ways of getting the sum of digits on the balls as odd?

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Q. A bag consists of

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balls each marked with one of the digits

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. If four balls are drawn successively with replacement from the bag, then the probability that no ball is marked with the digit

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is:

A bag consists of balls each marked with one of the digits 0 to 9. If four balls are drawn successively with replacement from the bag. What is the probability that none is marked with the digit 0?

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A bag contains 9 balls marked with digit 1,2,......9. If two balls are drawn from the bag, then numbers of ways getting the sum of the digits on balls as 10

The correct option is A 8The possible ways of getting the sum as 10:1+92+83+76+44+63+72+81+9So they are 8 ways

A bag contains $9$ balls marked with digit $1, 2, . . . . . .9$ . If two balls are drawn from the bag, then numbers of ways getting the sum of the digits on balls as $10$

The correct option is A $8$
The possible ways of getting the sum as $10 :$
$1 + 9 2 + 8 3 + 7 6 + 4 4 + 6 3 + 7 2 + 8 1 + 9$
So they are $8$ ways