Question

A bag contains $9$ discs of which $4$ are red, $3$ are blue and $2$ are yellow. The discs are similar in shape and size. If a disc is drawn at random from the bag, then the probability that it will be a red, is

• A. $\frac{4}{9}$
• B. $\frac{1}{3}$
• C. $\frac{2}{9}$
• D. $\frac{1}{9}$

Answer 1

The correct option is A $\frac{4}{9}$

There are $9$ discs in all so the total number of possible outcomes is $9$.
Let $A$ be the event that the disc is red.
$\therefore n\left(A\right)=4$
$\therefore P\left(A\right)=\frac{n\left(A\right)}{n\left(S\right)}=\frac{4}{9}$