A bag contains coins numbered from 1 to 50. If one coin is picked up at random, find the probability that it bears a square number.

True

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False

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$\frac{2}{3}$

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$\frac{1}{3}$

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Solution

The correct option is B
False

Given,
Numbers are marked from 1 to 50 on 50 coins
So, the total possible number of outcomes = 50

Number of perfect squares from 1- 50 = 1, 4, 9, 16, 25, 36, 49

= 7
$∴$ Number of favourable outcomes = 7
Probability of an event, P(E) = $= \frac{number of favourable outcomes}{total number of outcomes}$

$∴$ P (Square Numbered Coin) = $\frac{7}{50}$

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Similar questions

A bag contains 50 coins and each coin is marked from 51 to 100. One coin is picked at random.

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A bag contains 50 coins and each coin is marked from 51 to 100 . One coin is picked at random . The probability that the number on the coin is not a prime number is

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(B) 3/5

(D) 4/5

Q. A bag contains 50 coins and each coin is marked from 51 to 100. One coin is picked at random. The probability that the number on the coin is not a prime number, is

(a)

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n

of these coins have a head on both sides, whereas the remaining

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coins are fair. A coin is picked up at random from the bag and tossed. If the probability that the toss results in a head is

\frac{31}{42}

, then

n

is equal to

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