A bag contains six red four green and eight white balls If a ball is picked at random the probability that it is not white is

1/3

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4/9

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5/9

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2/3

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Solution

The correct option is D 5/9
Number of balls that are not white=10
Total=18
$∴$ P(not white)= $\frac{10}{18} = \frac{5}{9}$

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A bag contains six red four green and eight white balls If a ball is picked at random the probability that it is not white is

The correct option is D 5/9Number of balls that are not white=10Total=18∴ P(not white)=1018=59

The correct option is D 5/9
Number of balls that are not white=10
Total=18
$∴$ P(not white)= $\frac{10}{18} = \frac{5}{9}$