Question

A bag contains six white marbles and five red marbles. Find the number of ways in which four marbles can be drawn from the bag if
​​​​​​​A. They can be of any colour

Answer 1

Total no of marbles =6 white + 5 red =11 marbles
Since we have to draw 4 Marbles of any color from the 11 Marbles.
Hence required number of ways
${=}^{11}{C}_4$
$=\frac{11!}{(4!)(11-4)!}$
$=\frac{11\times 10\times 9\times 8\times (7!)}{(4\times 3\times 2\times 1)(7!)}$
$=330$