Question

A bag contains various coins of 50 paise, 25 paise, 20 paise and 10 paise in the ratio of 1:2:4:8 respectively. If the total amount in the bag is Rs. 52, how many coins of 20 paise does the bag have?

Answer 1

A bug contain coin 50 paise, 25 paise, 20 paise

& 10 paise in ratio $1:2:4:8$ respectively.

$\to$ Assume bag contain x coin.

So, 50 paise = x coin

25 pasie = 2x coin

20 paise = 4s coin

10 paise = 8x coin

$\to$ total amount in bag = 52 Rs

So, 527 = 5200 paise

$\to$ let,

$\therefore 50\times x+25\times 2x+20\times 4x+10\times 8x=5200$

$\therefore 260x=5200$

$\therefore x=20$ coin

$\to 20paise,$

coin for 20 paise $=4\times x$

$=4\times 20$

$=80$

So, the Ans is 80.