A bag has $20$ white balls, $10$ red balls and $15$ black balls. Find the fraction of red balls.

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Solution

Step 1: Find the total number of balls in the bag
The total number of balls in the bag $=$ the number of white balls $+$ the number of black balls $+$ the number of red balls
$=$ $20$ $+$ $15$ $+$ $10$
$=$ $45$

Step 2: Find the fraction of red balls in the bag
The fraction of red balls $= \frac{(t h e n u m b e r o f r e d b a l l s)}{(t h e t o t a l n u m b e r o f b a l l s)}$
$=$ $\frac{10}{45}$

Step 3: Simplify the fraction
Let's simplify $\frac{10}{45}$ :
The highest common factor of $10$ and $45$ is $9$ .
On dividing both the numerator and denominator by $5$ , we get:
$\frac{10 \div 5}{45 \div 5} = \frac{2}{9}$

Hence, the fraction of red balls in the bag is $\frac{10}{45}$ or $\frac{2}{9}$ .

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Similar questions

The pictograph given below shows the number of malls in a few cities.

Scale: $= 10$ malls, $= 5$ malls.

Observe the pictograph carefully and answer the following questions :

a) Which city has exactly $70$ malls ?

b) In which city did the builders construct most number of malls ?

c) Which two cities have equal number of malls ?

d) What is the total number of malls in all the cities ?

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