A bag has 3 red balls, 2 yellow balls and 3 black balls. They are drawn one by one and placed in a row. Find the number of ways they can be arranged.

280

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410

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560

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712

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478

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Solution

The correct option is C 560
Soln:

There are a total of 8 balls with 3 of one kind, 2 of other kind and rest 3 of the same kind. These can be arranged in $\frac{8!}{(3! \times 2! \times 3!)}$ = 560.

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A bag has 3 red balls, 2 yellow balls and 3 black balls. They are drawn one by one and placed in a row. Find the number of ways they can be arranged.

The correct option is C 560 Soln: There are a total of 8 balls with 3 of one kind, 2 of other kind and rest 3 of the same kind. These can be arranged in 8!(3!×2!×3!) = 560.

The correct option is C 560
Soln:

There are a total of 8 balls with 3 of one kind, 2 of other kind and rest 3 of the same kind. These can be arranged in $\frac{8!}{(3! \times 2! \times 3!)}$ = 560.