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Question

A bag of mass M hangs by a long thread and a bullet (mass m) comes horizontally with velocity v and gets caught in the bag. Then for the combined system (bag + bullet) :
  1. Momentum is mMv(M+m)
  2. KE is (12)Mv2
  3. Momentum is mv
  4. KE is m2v22(M+m)


Solution

The correct options are
C Momentum is mv
D KE is m2v22(M+m)
Since, Fext=0
Hence, momentum will remain conserved equal to mv.
mv=(m+M)v
v=mvm+M
and
final kinetic energy is 12(m+M)v2=m2v22(M+m)

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