A bag of wheat weighs 100 kg. To what height should it be raised, so that its potential energy may be 9800 J $(g = 9.8 m s^{- 2})$

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Solution

P.E $=$ mgh
$9800 = 100 \times 9.8 \times h$
$h = \frac{9800}{100 \times 9.8}$
$h = 10 m .$
$∴$ The bag of wheat should be raised to a height of 10 m.

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