Question

A bag with total $10$ balls contains $x$ blue and $y$ red balls. If the number of blue balls is four times the number of red, then write the two equations.

• A. $x+y=10,x=4y$
• B. $x-y=10,x=4y$
• C. $xy=10,x+4y=0$
• D. None of these

Answer 1

The correct option is A $x+y=10,x=4y$

Since total number of balls is $10$ and only blue $\left(x\right)$ and red balls $\left(y\right)$ are there in the bag.

$\Rightarrow x+y=10$

and number of blue balls is four time the number of red balls so,

$x=4y$

Hence option $A$ is correct choice