A ball B is at $300$ cm distance from origin on a line $37^{\circ}$ above horizontal. Another ball $A$ is projected directly aiming $B$ with initial velocity $700$ cm/s. At the same instant $B$ is released from its position. How far will $B$ has fallen when it is hit by $A$ ?

90 cm

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80 cm

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70 cm

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60 cm

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Solution

The correct option is D 60 cm
$\begin{matrix} x = A B cos 37^{0} = 300 \times \frac{4}{5} = 240 c m = 2.4 m t = \frac{2.4 m}{7} ∴ y = \frac{1}{2} g t^{2} = \frac{1}{2} \times 10 \times \frac{2.4}{7} \times \frac{2.4}{7} y = \frac{24 \times 2.4}{2 \times 7 \times 7} \approx 60 c m \end{matrix}$
$∴$ Option $D$ is correct.

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A ball B is at 300 cm distance from origin on a line 37∘ above horizontal. Another ball A is projected directly aiming B with initial velocity 700 cm/s. At the same instant B is released from its position. How far will B has fallen when it is hit by A?

The correct option is D 60 cmx=ABcos370=300×45=240cm=2.4mt=2.4m7∴y=12gt2=12×10×2.47×2.47y=24×2.42×7×7≈60cm∴ Option D is correct.

A ball B is at $300$ cm distance from origin on a line $37^{\circ}$ above horizontal. Another ball $A$ is projected directly aiming $B$ with initial velocity $700$ cm/s. At the same instant $B$ is released from its position. How far will $B$ has fallen when it is hit by $A$ ?