wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball dropped from a height of 2mrebounds to a height of 1.5m after hitting the ground. Then, the percentage of energy lost is


A

25

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

30

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

50

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

25


Step 1: Given data

Height from which ball is dropped, H=2m

Height to which ball rebound, h=1.5m

Step 2: Find the potential energy, P.E

Let mass of the ball is m

Potential energy at height H, P.E1=mgH

Potential energy at height h, P.E2=mgh

Step 3: Find the percentage loss in the potential energy

Loss in the potential energy, P.E=mg(H-h)

Percentage loss in the potential energy, %P.E=mg(H-h)mgH×100%

=mg(2-1.5)mg×2×100%=0.52×100%=25%

Hence, option (A) is correct.


flag
Suggest Corrections
thumbs-up
26
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon