A ball drops from a height of 4802 m. Thereafter it bounces every time to a height which is 14.28% less than its previous height. What height will the ball reach on its 4th bounce ?

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Solution

I wonder how many of you will notice that 14.28% = $\frac{1}{7}$ . Therefore the ball is rising up to a height which is $\frac{1^{t h}}{7}$ less than the previous height. Or the ball is rising up to a height which is $\frac{6}{7}$ of the previous height. Therefore on its 4th bounce the ball will reach a height of $4802 \times \frac{6}{7} \times \frac{6}{7} \times \frac{6}{7} \times \frac{6}{7} = 2592$ m

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