A ball falling freely from a height of 4-9 m- hits a horizontal surface- If e -3-4- then the ball will hit the surface- second time after A- 1-5 sB- 2-0 sC- 3-0 sD- 1-0 s

The correct option is A 1.5 sVelocity on hitting the surface nbsp; = √(2 × 9.8 × 4.9) = 9.8 m/s Velocity after first bounce nbsp; v = 34× 9.8 Time taken f ...

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Standard XII

Physics

Bouncing Ball Example

A ball fallin...

Question

A ball falling freely from a height of $4.9 m$ , hits a horizontal surface. If $e = \frac{3}{4}$ , then the ball will hit the surface, second time after

1.0 s

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1.5 s

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2.0 s

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3.0 s

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Solution

The correct option is B $1.5 s$
Velocity on hitting the surface
$= \sqrt{2 \times 9.8 \times 4.9}$
$= 9.8 m/s$
Velocity after first bounce
$v = \frac{3}{4} \times 9.8$
Time taken from first bounce to the second bounce $= \frac{2 v}{g}$
$= 2 \times \frac{3}{4} \times 9.8 \times \frac{1}{9.8}$
$1.5 s$

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A ball falling freely from a height of 4.9 m, hits a horizontal surface. If e=34, then the ball will hit the surface, second time after

The correct option is B 1.5 sVelocity on hitting the surface =√2×9.8×4.9 =9.8 m/s Velocity after first bounce v=34×9.8 Time taken from first bounce to the second bounce =2vg =2×34×9.8×19.8 1.5 s

A ball falling freely from a height of $4.9 m$ , hits a horizontal surface. If $e = \frac{3}{4}$ , then the ball will hit the surface, second time after