A ball falling freely from a height of 4.9m, hits a horizontal surface. If e=34, then the ball will hit the surface, second time after
A
1.0s
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B
1.5s
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C
2.0s
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D
3.0s
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Solution
The correct option is B1.5s Velocity on hitting the surface =√2×9.8×4.9 =9.8m/s
Velocity after first bounce v=34×9.8
Time taken from first bounce to the second bounce =2vg =2×34×9.8×19.8 1.5s