The correct option is C 10ms−1 and 5m
Given,
Time taken, t=1s
Initial velocity, u=0
Acceleration due to gravity, g=−10ms−2
(Upward direction is taken as positive)
Let the final speed be v.
From equation of motion,
v=u+gt
v=(0−10×1) ms−1
v=−10ms−1
Minus indicates velocity in downwards direction.
Let the height of table be h. Then displacement will be −h as the final position is below the initial position.
From equation of motion,
−h=ut+12gt2
−h=0×1−12×(−10)×12
h=5 m