A ball falls vertically after being dropped. The ball falls a distance d metres in a time of t seconds. d is directly proportional to the square of t.
The ball falls 20 metres in a time of 2 seconds.
The time (in seconds) that the ball takes to fall 605 m is

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Solution

The correct option is B
11

Given distance s is directly proportional to square of time t.

That is:
$s = k . t^{2} 20 = 4 k k = 5 So, s = 5 t^{2} 605 = 5 t^{2}$

t = 11 seconds

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A ball falls vertically after being dropped. It falls 20 metres in a time of 2 seconds. If 'd' is the distance in meters and t (in seconds) is the time taken where d is directly proportional to the square of t, how much time the ball will take to fall 605 m?

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A ball falls vertically after being dropped. The ball falls a distance d metres in a time of t seconds. d is directly proportional to the square of t. The ball falls 20 metres in a time of 2 seconds. The time (in seconds) that the ball takes to fall 605 m is

The correct option is B 11 Given distance s is directly proportional to square of time t. That is: s=k.t220=4kk=5So,s=5t2605=5t2 t = 11 seconds

A ball falls vertically after being dropped. The ball falls a distance d metres in a time of t seconds. d is directly proportional to the square of t.
The ball falls 20 metres in a time of 2 seconds.
The time (in seconds) that the ball takes to fall 605 m is

The correct option is B
11

Given distance s is directly proportional to square of time t.

That is:
$s = k . t^{2} 20 = 4 k k = 5 So, s = 5 t^{2} 605 = 5 t^{2}$

t = 11 seconds