Question

A ball floats on the surface of water in a container exposed to the atmosphere. Will the ball remain immersed at its initial depth or will it sink or rise somewhat if the container is shifted to the moon?

Answer 1

Let the volume immersed in the liquid initially be $V_s$ and mass of the body be $m$.

Since the body is floating, so mg force is balanced by buoyancy force.

So, $mg={\rho }_l{V}_{s}g$

We get, $V_s=\frac{m}{{\rho }_l}$

Thus, $V_s$ is independent og $g$.

On moon, value of $g$ changes but $V_s$ remains the same. Thus the body will remain immersed at its initial depth.