A ball hits a wall horizontally at 6-0 m s -1- It rebounds horizontally at 4-4 m s -1- The ball is in contact with the wall for 0-040 s- What is the acceleration of the ball-

Acceleration is simply the rate of change of velocity. nbsp; The initial velocity of the ball = nbsp; nbsp;6.0 ms minus;1 The final velocity of the ba ...

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Standard IX

Physics

The Equations of Motion

A ball hits a...

Question

A ball hits a wall horizontally at 6.0 m s⁻¹. It rebounds horizontally at 4.4 m s⁻¹. The ball is in contact with the wall for 0.040 s. What is the acceleration of the ball?

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Solution

Acceleration is simply the rate of change of velocity.

The initial velocity of the ball = 6.0 ms⁻¹

The final velocity of the ball = 4.4 ms⁻¹

Change in velocity = 4.4 ms⁻¹ $-$ 6.0 ms⁻¹ = $-$ 1.6 ms⁻¹

Time taken = 0.040 s

Acceleration of the ball = $\frac{- 1.6 {ms}^{- 1}}{0.040 s} = - 40 {ms}^{- 2}$

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A ball hits a wall horizontally at 6.0 m s−1. It rebounds horizontally at 4.4 m s−1​. The ball is in contact with the wall for 0.040 s. What is the acceleration of the ball?

Acceleration is simply the rate of change of velocity. The initial velocity of the ball = 6.0 ms−1 The final velocity of the ball = 4.4 ms−1 Change in velocity = 4.4 ms−1 - 6.0 ms−1 = -1.6 ms−1 Time taken = 0.040 s Acceleration of the ball = -1.6 ms-10.040 s=-40 ms-2

A ball hits a wall horizontally at 6.0 m s⁻¹. It rebounds horizontally at 4.4 m s⁻¹. The ball is in contact with the wall for 0.040 s. What is the acceleration of the ball?