A ball hits a wall horizontally at $6.0 {m s}^{- 1}$ . It rebounds horizontally at $4.4 {m s}^{- 1}$ , The ball the wall for $0.040 s$ . What is the acceleration of the ball?

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Solution

Acceleration $(a) = \frac{(v - u)}{t}$

$= \frac{6 - (- 4.4)}{0.040} = \frac{10.4}{0.040} = 260 m / s^{2}$

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A ball hits a wall horizontally at 6.0 ms−1. It rebounds horizontally at 4.4 ms−1, The ball the wall for 0.040 s. What is the acceleration of the ball?

Acceleration (a)=(v−u)t=6−(−4.4)0.040=10.40.040=260m/s2

A ball hits a wall horizontally at $6.0 {m s}^{- 1}$ . It rebounds horizontally at $4.4 {m s}^{- 1}$ , The ball the wall for $0.040 s$ . What is the acceleration of the ball?

Acceleration $(a) = \frac{(v - u)}{t}$

$= \frac{6 - (- 4.4)}{0.040} = \frac{10.4}{0.040} = 260 m / s^{2}$