A ball hits a wall horizontally at 6 m/s. It rebounds horizontally at 4.4m/s. The ball is in contact with the wall for 0.04 s. What is the acceleration of the ball?

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Solution

Assume ball was moving in forward direction then,
Initial velocity, u = 6 m/s ( forward)
Final velocity, v = 4.4 m/s ( backward) = -4.4 m/s
Time taken during change of velocity = 0.04 s
Acceleration = change in velocity/time = (v-u)/t
a = ( -4.4 -6)/ 0.04
a = -10.4/0.04
a = -1040/4
a = -260 m/s²
Acceleration of the ball is -260 m/s². It is opposite to initial velocity so it will act as retardation and slow down the ball.

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