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Byju's Answer
Standard XII
Physics
Newton's Laws for System of Particles
A ball hits t...
Question
A ball hits the ground and loses 20% of its momentum. Coefficient of restitution is (1) 0.2 (2) 0.4 (3) 0.6 (4) 0.8
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Q.
A ball hits the ground and loses 20% of its momentum. Coefficient of restitution is
Q.
A ball kept at a height of
5
m, is allowed to fall freely. It hits the ground. The coefficient of restitution is
0.6
What is the time interval between the first nd second rebound?(
g
=
10
m
/
s
2
)
Q.
In a
1
D
motion, ball
B
is ahead of
A
. Ball
A
is moving with a speed of
10
m/s
towards
B
and ball
B
is moving with speed
15
m/s
towards ball
A
. After the collision, ball
A
starts moving with a speed of
5
m/s
towards ball
B
and ball
B
starts moving with a speed of
20
m/s
away from
A
. Find the coefficient of restitution
(
e
)
.
Q.
If
1
√
0.
¯
¯
¯
2
+
√
0.
¯
¯
¯
4
+
1
√
0.
¯
¯
¯
4
+
√
0.
¯
¯
¯
6
+
1
√
0.
¯
¯
¯
6
+
√
0.
¯
¯
¯
8
+
1
√
0.
¯
¯¯¯
¯
10
+
√
0.
¯
¯¯¯
¯
12
+
1
√
0.
¯
¯¯¯
¯
12
+
√
0.
¯
¯¯¯
¯
14
+
1
√
0.
¯
¯¯¯
¯
14
+
√
0.
¯
¯¯¯
¯
16
+
1
√
0.
¯
¯¯¯
¯
16
+
√
0.
¯
¯¯¯
¯
18
+
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
+
1
√
0.
¯
¯¯¯
¯
38
+
√
0.
¯
¯¯¯
¯
40
=
3
2
(
√
a
+
√
b
)
,
where
a
>
b
,
a
and
b
are rational numbers, then (
a
÷
b
) is
यदि
1
√
0.
¯
¯
¯
2
+
√
0.
¯
¯
¯
4
+
1
√
0.
¯
¯
¯
4
+
√
0.
¯
¯
¯
6
+
1
√
0.
¯
¯
¯
6
+
√
0.
¯
¯
¯
8
+
1
√
0.
¯
¯¯¯
¯
10
+
√
0.
¯
¯¯¯
¯
12
+
1
√
0.
¯
¯¯¯
¯
12
+
√
0.
¯
¯¯¯
¯
14
+
1
√
0.
¯
¯¯¯
¯
14
+
√
0.
¯
¯¯¯
¯
16
+
1
√
0.
¯
¯¯¯
¯
16
+
√
0.
¯
¯¯¯
¯
18
+
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
+
1
√
0.
¯
¯¯¯
¯
38
+
√
0.
¯
¯¯¯
¯
40
=
3
2
(
√
a
+
√
b
)
,
जहाँ
a
>
b
,
a
तथा
b
परिमेय संख्याएँ हैं, तब (
a
÷
b
) का मान है
Q.
A ball is dropped from a height of 1 m. if coefficient of restitution between the surface and the ball is 0.6, the ball rebounds to a height of
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