Question

A ball is dropped from a certain height. If it takes 0.2 s to cross the last 6.2 m before hitting the ground, find the height from which it was dropped.

Answer 1

$S=ut+\frac{1}{2}a{t}^2$
Velocity at the beginning of 0.2 s = velocity after it travelled (h - 6.2 m)
So, total distance = 51.2 meters