A ball is dropped from a height $h$ on a floor of coefficient of restitution $e$ . The total distance covered by the ball just before second hit is

h (1 - 2 e^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

h (1 + 2 e^{2})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

h (1 + e^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

h e^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $h (1 + 2 e^{2})$
Total distance travelled by the ball before its second hit is
$H = h + 2 h_{1}$
$= h [1 + 2 e^{2}]$ $[∵ h_{1} = h e^{2}]$

Suggest Corrections

Similar questions

Q. A ball is dropped from height

h

on a floor. If the coefficient of restitution is

e

, find the total distance covered by the ball before coming to rest on the ground.

A ball is dropped onto a fixed horizontal surface from height h₀. The coefficient of restitution is ‘e’. The total distance ‘D’ travelled by ball before it comes to rest on the surface.

A ball is dropped onto a fixed horizontal surface from height h₀. The coefficient of restitution is e. Find the total distance D travelled by the ball before it comes to rest on the surface.

Q. A particle is dropped from a height

h

on a floor, if the coefficient of restitution is

e

. Find the time taken by ball before second bounce.

A ball is dropped from a height $h_{0}$ on a horizontal floor and keeps rebounding after hitting the floor. Find: (i) speed after $n$ rebounds

(ii) Total distance travelled by the ball before stopping

(iii) Height it rises after nth rebound

(iv) Total time before stopping

(coefficient of restitution is $e$ )

Join BYJU'S Learning Program

A ball is dropped from a height h on a floor of coefficient of restitution e. The total distance covered by the ball just before second hit is

The correct option is B h(1+2e2)Total distance travelled by the ball before its second hit isH=h+2h1 =h[1+2e2] [∵h1=he2]

A ball is dropped from a height $h$ on a floor of coefficient of restitution $e$ . The total distance covered by the ball just before second hit is

The correct option is B $h (1 + 2 e^{2})$
Total distance travelled by the ball before its second hit is
$H = h + 2 h_{1}$
$= h [1 + 2 e^{2}]$ $[∵ h_{1} = h e^{2}]$