A ball is dropped from height ′h′ as shown. The collision is perfectly inelastic. Select the correct alternative(s)
The momentum will remain conserved for the following. For the velocity just after collision, change in position Δx will be zero.
The velocity of the ball when it hits the block can be calculated as follows,
mgh=12mv2
v=√2gh
Using the principle of conservation of momentum
m(√2gh)+M(0)=(m+M)V′
V′=mm+M(√2gh)