A ball is dropped from height h on a horizontal floor. If it is loses 60% of its energy in hitting the floor then height upto which it will rose after rebounce is

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Solution

Dear student
Let the bal is dropped from the height H
Total potential energy stored = mgH
as it lost it's 60% of energy on hitting the ground
Energy at the bottom is 0.4mgH
again it will lose energy while rebouncing
0.4 $\times$ 0.4mgH = 0.16mgH
now using law of conservation of energy
mg $H_{1}$ = 0.16mgH
where $H_{1}$ is the height to which ball rebounds
$H_{1}$ = 0.16H
Regards

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