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Question
A ball is dropped from the roof of a building. It takes 10seconds to reach the ground. Find the height of the building.(g=9.8m/s2
A ball is dropped from the roof of a building. It takes 10seconds to reach the ground. Find the height of the building.(g=9.8m/s2
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Solution
Given:Initial speed =u = 0 m/s( free fall)
Time =t = 10 sec
a=g= 9.8m/ s2
Height = h = ?
Formula to be used:Second equation of motion:
h= ut + 1/2at^2
h= 0xt+(1/2)×9.8 × 10x10
= 4.9 x 100
= 490m
Therefore the height of building is 490m.
Given:Initial speed =u = 0 m/s( free fall)
Time =t = 10 sec
a=g= 9.8m/ s2
Height = h = ?
Formula to be used:Second equation of motion:
h= ut + 1/2at^2
h= 0xt+(1/2)×9.8 × 10x10
= 4.9 x 100
= 490m
Therefore the height of building is 490m.
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