A ball is dropped from the roof of a building. It takes 10seconds to reach the ground. Find the height of the building.(g=9.8m/s2
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Solution
Given:Initial speed =u = 0 m/s( free fall) Time =t = 10 sec a=g= 9.8m/ s2 Height = h = ? Formula to be used:Second equation of motion: h= ut + 1/2at^2 h= 0xt+(1/2)×9.8 × 10x10 = 4.9 x 100 = 490m Therefore the height of building is 490m.