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Question

A ball is dropped from the top of a building. The ball takes 0.5 s to fall past the 3 m length of a window at certain distance from the top of the building. Time of travel above the window is (Take g=10m/s2)

A
0.5 s
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B
0.25 s
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C
0.35 s
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D
0.75 s
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Solution

The correct option is C 0.35 s
s=ut+12gt2
3=u(0.5)+12×10(0.5)2
3=(0.5)u+5(0.25)
1.750.5=u
u=3.5 m/s
v1=u=3.5m/s
v1=u1+gt
3.5=10(t)t=0.35 sec

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