A ball is dropped from the top of a building whose height is $20 m$ . $T a k e g = 10 m / s^{2}$
b) Find the time taken by the ball to reach the ground.

2 s

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3 s

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1 s

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4 s

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Solution

The correct option is A $2 s$
Given:
$s = 20 m$
$a = 10 m / s^{2}$
$u = 0$

Using equation of motion:
$s = u t + 1 / 2 a t^{2}$
$20 = 0 + 1 / 2 \times 10 \times t^{2}$
$t^{2} = 4$
$t = 2 s$

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A ball is dropped from the top of a building whose height is 20 m. Take g=10m/s2 b) Find the time taken by the ball to reach the ground.

The correct option is A 2 sGiven: s=20 m a=10 m/s2 u=0 Using equation of motion: s=ut + 1/2at2 20=0 + 1/2×10×t2 t2=4 t=2 s

A ball is dropped from the top of a building whose height is $20 m$ . $T a k e g = 10 m / s^{2}$
b) Find the time taken by the ball to reach the ground.

The correct option is A $2 s$
Given:
$s = 20 m$
$a = 10 m / s^{2}$
$u = 0$

Using equation of motion:
$s = u t + 1 / 2 a t^{2}$
$20 = 0 + 1 / 2 \times 10 \times t^{2}$
$t^{2} = 4$
$t = 2 s$