wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball is dropped from the top of a tower 120 m high and simultaneously another ball is projected vertically upwards from the ground with a speed of 30 m/s. The two balls will meet after

A
2 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4 s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 4 s
Let x be the distance from the top of tower, where the balls projected will meet
For ball freely falling body we know that the displacement covered is s=12at2, where t is the time when both balls meet.

x=12gt2 ...(i)

For ball projected upwards: the displcement is (120x)
120x=30t12gt2
From (i) and (ii)

12012gt2=30t12gt2

30t=120
t=4 s

Hence option C is the corect answer

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Gravity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon