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Question

A ball is dropped from the top of a tower. Another ball is thrown up vertically with a velocity of $$20$$ $$m/s$$ from the ground level at the same instant and meets the first ball after $$1.5$$ seconds. Height of the tower is


A
20 m
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B
30 m
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C
40 m
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D
50 m
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Solution

The correct option is D 30 m
For A: $$s_A = \dfrac {1}{2}gt^2$$
For B: $$s_B = 20(t) - \dfrac {1}{2}gt^2$$
$$s_A + s_B = 20t = H$$
$$t = 1.5\ sec$$
$$\Rightarrow H = 30\ m$$

Physics

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