Question

# A ball is dropped from the top of a tower. Another ball is thrown up vertically with a velocity of $$20$$ $$m/s$$ from the ground level at the same instant and meets the first ball after $$1.5$$ seconds. Height of the tower is

A
20 m
B
30 m
C
40 m
D
50 m

Solution

## The correct option is D 30 mFor A: $$s_A = \dfrac {1}{2}gt^2$$For B: $$s_B = 20(t) - \dfrac {1}{2}gt^2$$$$s_A + s_B = 20t = H$$$$t = 1.5\ sec$$$$\Rightarrow H = 30\ m$$Physics

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