A ball is dropped from top of the tower. The ratio of distance travelled by the ball in first and third second of the motion is :

1 : 3

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3 : 5

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1 : 5

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3 : 7

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Solution

The correct option is C 1 : 5
Distance travelled in 1st second is $s_{1} = \frac{1}{2} a 1^{2} = \frac{1}{2} a$ . Distance travelled in 3rd second is $s_{3} = \frac{1}{2} a (2^{2} - 1^{2}) = \frac{1}{2} 5 a$ .
Therefore the ratio is 1:5

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A ball is dropped from top of the tower. The ratio of distance travelled by the ball in first and third second of the motion is :

The correct option is C 1 : 5Distance travelled in 1st second is s1=12a12=12a. Distance travelled in 3rd second is s3=12a(22−12)=125a. Therefore the ratio is 1:5

The correct option is C 1 : 5
Distance travelled in 1st second is $s_{1} = \frac{1}{2} a 1^{2} = \frac{1}{2} a$ . Distance travelled in 3rd second is $s_{3} = \frac{1}{2} a (2^{2} - 1^{2}) = \frac{1}{2} 5 a$ .
Therefore the ratio is 1:5