A ball is gently dropped from a height of 20 m. If it's velocity increases uniformly at the rate of 10 m/s², with what velocity will it strike the ground? After what time will it strike the ground?
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Solution
Given that, Distance(s)="20m" Initial velocity(u)=0m/s Accelaration="10m/s-2"
Using the relation Distance-Time
s=v2 - u2=2a
s= v2-0=2*10 20=v2-0=20 v2-0=20*20 v2=400(underoot) v=20 m/s
time=v=u=at 20=0+10 20 upon 10=0+10(t)= time= 2 secs