Question

A ball is held at rest in position $A$ as shown in the figure by two light cords. The horizontal cord is cut and the ball swings as a pendulum. What is the ratio of the tensions in the supporting cord of length $l$ , in position $A$ to that in position $B$ ?

Answer 1

Let the Tension on the horizon at

cord and cord of length l be T,

and T

So in balancing condition A

$T,=Tsin\theta ....\left(1\right)$

$mg=Tcos\theta ...\left(2\right)$

m position $Bmg=T^{\prime }cos\theta$...(3)

(3)/(2) L $=\frac{T^{\prime }}{T}$

So The ratio of the two tensions at position A and B in one