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Question

A ball is is dropped on the floor from a height of 10 m. It rebounds to a height of 2.5 m. If the ball is in contact with the floor for 0.01 s, the average acceleration during contact is

A
2100 m/s2 downwards
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B
2100 m/s2 upwards
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C
1400 m/s2
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D
700 m/s2
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Solution

The correct option is B 2100 m/s2 upwards
Velocity of ball at the time of striking the floor,
u=(2gh1)=(2×9.8×10)
=14 m/s (downwards)
Velocity with which it rebounds,
v=(2gh2)=(2×9.8×2.5)
=7 m/s (upwards)
Average Acceleration during contact is
a=vut2t1=7(14)0.01
=210.01=2100 m/s2 upwards
(Taking upward as positive and downward as negative )

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