1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A ball is projected at an angle 45∘ with horizontal from a point on ground 10m away from a vertical wall. It just crosses the wall to land on the ground at a distance 40m from the wall on other side. Then the height of the wall is:

A
20 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
10 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C 8 mEquation of projectile is y=ntanθ(1−nR)Total distance the ball covers before falling =10+40=50 m∴Range =50mNow, y=10tan450(1−1050)=10×1×4050=2×4=8mHeight of wall =8 mHence Option C is correct.

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Problem Solving Using Newton's Laws
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program