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2D Motion as Two 1D Motions

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Question

A ball is projected from a point on an inclined plane horizontally. It takes $\frac{1}{\sqrt{2}}$ seconds to strike the plane. If the incline plane makes an angle of $30^{\circ}$ with horizontal, then find the range of the ball on incline plane in meters. [g = 10 $m / s^{2}$ ] ___

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Solution

$A C = \frac{1}{2} \times 10 \times {(\frac{1}{\sqrt{2}})}^{2} = 2.5 m \Rightarrow A B = 5 m$

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