Question

A ball is projected from a point on the floor with a speed of $15m/s$ at an angle of ${60}^o$ with the horizontal. Will it hit a vertical wall $5m$ away from the point of projection and perpendicular to the plane of projection without hitting the floor? Will the answer differ if the wall is $22m$ away?

Answer 1

Here,

$u=15m/s,$

$\theta ={60}^0,$

$g=9.8m/s^2$

Formula for range of the ball

$x=\frac{u^2\sin 2\theta }{g}$

$=\frac{{15}^2\sin 2\times 60}{9.8}$

$=\frac{225\sin 120}{9.8}$

$\therefore x=19.8m$

So in the first case, the wall is 5m away from projection point so it is in the horizontal range of projectile. So the ball will hit the wall.

In the second case, (22m away ) wall is not within the horizontal range. So the ball would not hit the wall.