Question

A ball is projected from point A with a velocity $10m{s}^{-1}$ perpendicular to the plane as given. The range of the ball on plane is ( in m), +

• A. $\frac{40}{3}$
• B. $\frac{20}{13}$
• C. $\frac{13}{20}$
• D. $\frac{13}{40}$

Answer 1

The correct option is A $\frac{40}{3}$


$T=\frac{2\times 10s}{5\sqrt{3}}$
Range along incline,
$R=u_{x}T+\frac{1}{2}{a}_x{T}^2=(0\times T)+[\frac{1}{2}\times 5\times {\left(\frac{2\times 10}{5\sqrt{3}}\right)}^2]$
$\Rightarrow R=\frac{40m}{3}$