1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball is projected horizontally relative to the plane with a speed v from the top of a plane inclined at an angle 450 with the horizontal. How far from the point of projection will the ball strike the plane?

A
v2g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2v2g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2v2g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
22v2g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2√2v2gWriting equation of motion in normal to incline plane: Sy=vsinαt−gcosαt22For Range , Sy=0 which gives t=2vsinαgcosαSx=vcosαt+gsinαt22Replacing the value of t, writing Equation of motion in along incline planeSx=(vcosα)t+(gsinα2)(t2)Sx=(vcosα)(2Vsinαgcosα)+(gsinα2)(2Vsinαgcosβ2)Sx=2v2sinαgcosα(cosα+sin2αcosα) Sx=2v2g(1√2+1√2)=2√2v2g

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Realistic Collisions
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program