wiz-icon
MyQuestionIcon
MyQuestionIcon
11
You visited us 11 times! Enjoying our articles? Unlock Full Access!
Question

A ball is projected in a direction inclined to the horizontal and it bounces on a horizontal plane. If the range of first rebound is R and coefficient of restitution is e, then range of the next rebound is


A
R=eR
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
R=e2R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
R=Re
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
R=R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A R=eR

As we know that,
Range =ux×T
here, ux is horizontal component of velocity
ux=ucosθ
uy=usinθ= vertical component of velocity
Time of flight, T=2usinθg
T=2uyg
Hence, Range R=uxT
R=2uxuyg
After rebound, horizontal component will not change but vertical component of velocity will be decreased by e times, therefore, uy=e×uy
Therefore new range, R=2ux×uyg
R=2euxuyg=e.2uxuyg=eR

flag
Suggest Corrections
thumbs-up
11
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon