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Oblique Collision

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Question

A ball is projected on smooth inclined plane in direction perpendicular to line of greatest slope with velocity of $8 m / s$ . It's speed after $1 s$ is (take $g$ $=$ 10 m/s $^{2}$ )

10 m/s

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15 m/s

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12 m/s

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16 m/s

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Solution

The correct option is A 10 m/s
Given the ball is projected perpendicular to the line of greatest slope .
$⟹$ The ball is projected on the inclined plane parallel to the horizontal .
There is no acceleration in this direction and hence , $8$ m/s remains constant in this direction .
Component of acceleration downwards the incline is $g s i n θ$
Velocity in this direction as a function of time is $V_{y} = g s i n θ * t$
Hence , total velocity is $= \sqrt{8^{2} + g^{2} s i n^{2} 37^{\circ}} = \sqrt{64 + 36} = 10$ m/s .

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A ball is projected on smooth inclined plane in direction perpendicular to line of greatest slope with velocity of 8 m/s. It's speed after 1 s is (take g =10 m/s2)

A ball is projected on smooth inclined plane in direction perpendicular to line of greatest slope with velocity of $8 m / s$ . It's speed after $1 s$ is (take $g$ $=$ 10 m/s $^{2}$ )