A ball is projected vertically upward from the ground. If the ball is at height $h$ at $t = 4 s$ and $5 s$ , than the value of $h$ is

101.25 m

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100 m

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95 m

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105 m

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Solution

The correct option is B $100 m$
It means it took $1$ second to reach from A to B.
Due to symmetry it will take $0.5$ second to reach from A to C.
Hence total time to reach from ground to C = $4 + 0.5 = \frac{9}{2} s e c$
Maximum height = $\frac{1}{2} \times g \times (\frac{9}{2})^{2} = 101.25 m$
Length covered from C to B = $0 + \frac{1}{2} \times g \times (\frac{1}{2})^{2} = 1.25 m$
$∴$ h = Maximum height - CB
$= 101.25 - 1.25 = 100 m$

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A ball is projected vertically upward from the ground. If the ball is at height h at t=4s and 5s, than the value of h is

A ball is projected vertically upward from the ground. If the ball is at height $h$ at $t = 4 s$ and $5 s$ , than the value of $h$ is