A ball is released from the top of a tower of height h metre. It takes T seconds to reach the ground. What is the height of the ball from the ground after T3 second?
A
17h/9 from the ground
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B
8h/9 from the ground
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C
7h/9 from the ground
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D
h/9 from the ground
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Solution
The correct option is B8h/9 from the ground For free fall H=gt2/2
Put H=h we should get time as t=T so T2=2h/g..................... 1
put t=T/3 in eqaution-1 we get
H=g(T/3)22g=gT2/18g=h/9
This H is displacement from initial point i.e height fall from top point so height from the ground will be h−h/9=8h/9